Integrand size = 46, antiderivative size = 349 \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}+\frac {\left (\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 (3 b e-a i)\right ) \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{256 a^{13/4} b^{7/4}}+\frac {\left (15 b e+\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 a i\right ) \text {arctanh}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{256 a^{13/4} b^{7/4}}+\frac {(5 b d-a h) \text {arctanh}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{32 a^{7/2} b^{3/2}} \]
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Time = 0.35 (sec) , antiderivative size = 349, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {1872, 1868, 1869, 1890, 281, 214, 1181, 211} \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\frac {\arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right ) \left (\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 (3 b e-a i)\right )}{256 a^{13/4} b^{7/4}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right ) \left (\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 a i+15 b e\right )}{256 a^{13/4} b^{7/4}}+\frac {\text {arctanh}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right ) (5 b d-a h)}{32 a^{7/2} b^{3/2}}+\frac {x \left (7 (11 b c-a g)+12 x (5 b d-a h)+15 x^2 (3 b e-a i)\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {x \left (b (11 b c-a g)+2 b x (5 b d-a h)+3 b x^2 (3 b e-a i)\right )+4 a (2 b f-a j)}{96 a^2 b^2 \left (a-b x^4\right )^2}+\frac {x \left (x (a h+b d)+x^2 (a i+b e)+x^3 (a j+b f)+a g+b c\right )}{12 a b \left (a-b x^4\right )^3} \]
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Rule 211
Rule 214
Rule 281
Rule 1181
Rule 1868
Rule 1869
Rule 1872
Rule 1890
Rubi steps \begin{align*} \text {integral}& = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}-\frac {\int \frac {-b (11 b c-a g)-2 b (5 b d-a h) x-3 b (3 b e-a i) x^2-4 b (2 b f-a j) x^3}{\left (a-b x^4\right )^3} \, dx}{12 a b^2} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}+\frac {\int \frac {7 b (11 b c-a g)+12 b (5 b d-a h) x+15 b (3 b e-a i) x^2}{\left (a-b x^4\right )^2} \, dx}{96 a^2 b^2} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}-\frac {\int \frac {-21 b (11 b c-a g)-24 b (5 b d-a h) x-15 b (3 b e-a i) x^2}{a-b x^4} \, dx}{384 a^3 b^2} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}-\frac {\int \left (-\frac {24 b (5 b d-a h) x}{a-b x^4}+\frac {-21 b (11 b c-a g)-15 b (3 b e-a i) x^2}{a-b x^4}\right ) \, dx}{384 a^3 b^2} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}-\frac {\int \frac {-21 b (11 b c-a g)-15 b (3 b e-a i) x^2}{a-b x^4} \, dx}{384 a^3 b^2}+\frac {(5 b d-a h) \int \frac {x}{a-b x^4} \, dx}{16 a^3 b} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}+\frac {(5 b d-a h) \text {Subst}\left (\int \frac {1}{a-b x^2} \, dx,x,x^2\right )}{32 a^3 b}+\frac {\left (15 b e+\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 a i\right ) \int \frac {1}{\sqrt {a} \sqrt {b}-b x^2} \, dx}{256 a^3 b}-\frac {\left (\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 (3 b e-a i)\right ) \int \frac {1}{-\sqrt {a} \sqrt {b}-b x^2} \, dx}{256 a^3 b} \\ & = \frac {x \left (b c+a g+(b d+a h) x+(b e+a i) x^2+(b f+a j) x^3\right )}{12 a b \left (a-b x^4\right )^3}+\frac {x \left (7 (11 b c-a g)+12 (5 b d-a h) x+15 (3 b e-a i) x^2\right )}{384 a^3 b \left (a-b x^4\right )}+\frac {4 a (2 b f-a j)+x \left (b (11 b c-a g)+2 b (5 b d-a h) x+3 b (3 b e-a i) x^2\right )}{96 a^2 b^2 \left (a-b x^4\right )^2}+\frac {\left (\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 (3 b e-a i)\right ) \tan ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{256 a^{13/4} b^{7/4}}+\frac {\left (15 b e+\frac {7 \sqrt {b} (11 b c-a g)}{\sqrt {a}}-5 a i\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{256 a^{13/4} b^{7/4}}+\frac {(5 b d-a h) \tanh ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{32 a^{7/2} b^{3/2}} \\ \end{align*}
Time = 0.34 (sec) , antiderivative size = 439, normalized size of antiderivative = 1.26 \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\frac {-\frac {4 a b x (-77 b c+7 a g-15 b x (4 d+3 e x)+3 a x (4 h+5 i x))}{a-b x^4}-\frac {16 a^2 \left (12 a^2 j-b^2 x (11 c+x (10 d+9 e x))+a b x (g+x (2 h+3 i x))\right )}{\left (a-b x^4\right )^2}+\frac {128 a^3 \left (a^2 j+b^2 x (c+x (d+e x))+a b (f+x (g+x (h+i x)))\right )}{\left (a-b x^4\right )^3}+6 \sqrt [4]{a} \sqrt [4]{b} \left (77 b^{3/2} c-15 \sqrt {a} b e-7 a \sqrt {b} g+5 a^{3/2} i\right ) \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )+3 \sqrt [4]{a} \sqrt [4]{b} \left (-77 b^{3/2} c-40 \sqrt [4]{a} b^{5/4} d-15 \sqrt {a} b e+7 a \sqrt {b} g+8 a^{5/4} \sqrt [4]{b} h+5 a^{3/2} i\right ) \log \left (\sqrt [4]{a}-\sqrt [4]{b} x\right )+3 \sqrt [4]{a} \sqrt [4]{b} \left (77 b^{3/2} c-40 \sqrt [4]{a} b^{5/4} d+15 \sqrt {a} b e-7 a \sqrt {b} g+8 a^{5/4} \sqrt [4]{b} h-5 a^{3/2} i\right ) \log \left (\sqrt [4]{a}+\sqrt [4]{b} x\right )-24 \sqrt {a} \sqrt {b} (-5 b d+a h) \log \left (\sqrt {a}+\sqrt {b} x^2\right )}{1536 a^4 b^2} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 1.60 (sec) , antiderivative size = 256, normalized size of antiderivative = 0.73
method | result | size |
risch | \(\frac {-\frac {5 \left (a i -3 b e \right ) b \,x^{11}}{128 a^{3}}-\frac {\left (a h -5 b d \right ) b \,x^{10}}{32 a^{3}}-\frac {7 \left (a g -11 b c \right ) b \,x^{9}}{384 a^{3}}+\frac {7 \left (a i -3 b e \right ) x^{7}}{64 a^{2}}+\frac {\left (a h -5 b d \right ) x^{6}}{12 a^{2}}+\frac {3 \left (a g -11 b c \right ) x^{5}}{64 a^{2}}+\frac {j \,x^{4}}{8 b}+\frac {\left (5 a i +113 b e \right ) x^{3}}{384 a b}+\frac {\left (a h +11 b d \right ) x^{2}}{32 a b}+\frac {\left (7 a g +51 b c \right ) x}{128 a b}-\frac {a j -2 b f}{24 b^{2}}}{\left (-b \,x^{4}+a \right )^{3}}-\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{4} b -a \right )}{\sum }\frac {\left (-5 \left (a i -3 b e \right ) \textit {\_R}^{2}-8 \left (a h -5 b d \right ) \textit {\_R} -7 a g +77 b c \right ) \ln \left (x -\textit {\_R} \right )}{\textit {\_R}^{3}}}{512 a^{3} b^{2}}\) | \(256\) |
default | \(\frac {-\frac {5 \left (a i -3 b e \right ) b \,x^{11}}{128 a^{3}}-\frac {\left (a h -5 b d \right ) b \,x^{10}}{32 a^{3}}-\frac {7 \left (a g -11 b c \right ) b \,x^{9}}{384 a^{3}}+\frac {7 \left (a i -3 b e \right ) x^{7}}{64 a^{2}}+\frac {\left (a h -5 b d \right ) x^{6}}{12 a^{2}}+\frac {3 \left (a g -11 b c \right ) x^{5}}{64 a^{2}}+\frac {j \,x^{4}}{8 b}+\frac {\left (5 a i +113 b e \right ) x^{3}}{384 a b}+\frac {\left (a h +11 b d \right ) x^{2}}{32 a b}+\frac {\left (7 a g +51 b c \right ) x}{128 a b}-\frac {a j -2 b f}{24 b^{2}}}{\left (-b \,x^{4}+a \right )^{3}}+\frac {\frac {\left (-7 a g +77 b c \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )+2 \arctan \left (\frac {x}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )\right )}{4 a}+\frac {\left (-8 a h +40 b d \right ) \ln \left (\frac {a +x^{2} \sqrt {a b}}{a -x^{2} \sqrt {a b}}\right )}{4 \sqrt {a b}}-\frac {\left (-5 a i +15 b e \right ) \left (2 \arctan \left (\frac {x}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )-\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )\right )}{4 b \left (\frac {a}{b}\right )^{\frac {1}{4}}}}{128 a^{3} b}\) | \(362\) |
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Timed out. \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\text {Timed out} \]
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Time = 0.30 (sec) , antiderivative size = 463, normalized size of antiderivative = 1.33 \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=-\frac {15 \, {\left (3 \, b^{4} e - a b^{3} i\right )} x^{11} + 12 \, {\left (5 \, b^{4} d - a b^{3} h\right )} x^{10} + 7 \, {\left (11 \, b^{4} c - a b^{3} g\right )} x^{9} + 48 \, a^{3} b j x^{4} - 42 \, {\left (3 \, a b^{3} e - a^{2} b^{2} i\right )} x^{7} - 32 \, {\left (5 \, a b^{3} d - a^{2} b^{2} h\right )} x^{6} - 18 \, {\left (11 \, a b^{3} c - a^{2} b^{2} g\right )} x^{5} + 32 \, a^{3} b f - 16 \, a^{4} j + {\left (113 \, a^{2} b^{2} e + 5 \, a^{3} b i\right )} x^{3} + 12 \, {\left (11 \, a^{2} b^{2} d + a^{3} b h\right )} x^{2} + 3 \, {\left (51 \, a^{2} b^{2} c + 7 \, a^{3} b g\right )} x}{384 \, {\left (a^{3} b^{5} x^{12} - 3 \, a^{4} b^{4} x^{8} + 3 \, a^{5} b^{3} x^{4} - a^{6} b^{2}\right )}} + \frac {\frac {8 \, {\left (5 \, b d - a h\right )} \log \left (\sqrt {b} x^{2} + \sqrt {a}\right )}{\sqrt {a} \sqrt {b}} - \frac {8 \, {\left (5 \, b d - a h\right )} \log \left (\sqrt {b} x^{2} - \sqrt {a}\right )}{\sqrt {a} \sqrt {b}} + \frac {2 \, {\left (77 \, b^{\frac {3}{2}} c - 15 \, \sqrt {a} b e - 7 \, a \sqrt {b} g + 5 \, a^{\frac {3}{2}} i\right )} \arctan \left (\frac {\sqrt {b} x}{\sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}} \sqrt {b}} - \frac {{\left (77 \, b^{\frac {3}{2}} c + 15 \, \sqrt {a} b e - 7 \, a \sqrt {b} g - 5 \, a^{\frac {3}{2}} i\right )} \log \left (\frac {\sqrt {b} x - \sqrt {\sqrt {a} \sqrt {b}}}{\sqrt {b} x + \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}} \sqrt {b}}}{512 \, a^{3} b} \]
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Leaf count of result is larger than twice the leaf count of optimal. 633 vs. \(2 (302) = 604\).
Time = 0.28 (sec) , antiderivative size = 633, normalized size of antiderivative = 1.81 \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=-\frac {\sqrt {2} {\left (77 \, b^{3} c - 7 \, a b^{2} g - 40 \, \sqrt {2} \left (-a b^{3}\right )^{\frac {1}{4}} b^{2} d + 8 \, \sqrt {2} \left (-a b^{3}\right )^{\frac {1}{4}} a b h - 15 \, \sqrt {-a b} b^{2} e + 5 \, \sqrt {-a b} a b i\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x + \sqrt {2} \left (-\frac {a}{b}\right )^{\frac {1}{4}}\right )}}{2 \, \left (-\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{512 \, \left (-a b^{3}\right )^{\frac {3}{4}} a^{3} b} - \frac {\sqrt {2} {\left (77 \, b^{3} c - 7 \, a b^{2} g + 40 \, \sqrt {2} \left (-a b^{3}\right )^{\frac {1}{4}} b^{2} d - 8 \, \sqrt {2} \left (-a b^{3}\right )^{\frac {1}{4}} a b h - 15 \, \sqrt {-a b} b^{2} e - 5 \, \sqrt {-a b} a b i\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x - \sqrt {2} \left (-\frac {a}{b}\right )^{\frac {1}{4}}\right )}}{2 \, \left (-\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{512 \, \left (-a b^{3}\right )^{\frac {3}{4}} a^{3} b} - \frac {\sqrt {2} {\left (77 \, b^{3} c - 7 \, a b^{2} g - 15 \, \sqrt {-a b} b^{2} e + 5 \, \sqrt {-a b} a b i\right )} \log \left (x^{2} + \sqrt {2} x \left (-\frac {a}{b}\right )^{\frac {1}{4}} + \sqrt {-\frac {a}{b}}\right )}{1024 \, \left (-a b^{3}\right )^{\frac {3}{4}} a^{3} b} + \frac {\sqrt {2} {\left (77 \, b^{3} c - 7 \, a b^{2} g - 15 \, \sqrt {-a b} b^{2} e + 5 \, \sqrt {-a b} a b i\right )} \log \left (x^{2} - \sqrt {2} x \left (-\frac {a}{b}\right )^{\frac {1}{4}} + \sqrt {-\frac {a}{b}}\right )}{1024 \, \left (-a b^{3}\right )^{\frac {3}{4}} a^{3} b} - \frac {45 \, b^{4} e x^{11} - 15 \, a b^{3} i x^{11} + 60 \, b^{4} d x^{10} - 12 \, a b^{3} h x^{10} + 77 \, b^{4} c x^{9} - 7 \, a b^{3} g x^{9} - 126 \, a b^{3} e x^{7} + 42 \, a^{2} b^{2} i x^{7} - 160 \, a b^{3} d x^{6} + 32 \, a^{2} b^{2} h x^{6} - 198 \, a b^{3} c x^{5} + 18 \, a^{2} b^{2} g x^{5} + 48 \, a^{3} b j x^{4} + 113 \, a^{2} b^{2} e x^{3} + 5 \, a^{3} b i x^{3} + 132 \, a^{2} b^{2} d x^{2} + 12 \, a^{3} b h x^{2} + 153 \, a^{2} b^{2} c x + 21 \, a^{3} b g x + 32 \, a^{3} b f - 16 \, a^{4} j}{384 \, {\left (b x^{4} - a\right )}^{3} a^{3} b^{2}} \]
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Time = 10.57 (sec) , antiderivative size = 2764, normalized size of antiderivative = 7.92 \[ \int \frac {c+d x+e x^2+f x^3+g x^4+h x^5+i x^6+j x^7}{\left (a-b x^4\right )^4} \, dx=\text {Too large to display} \]
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